Как сгруппировать элементы xml с помощью xslt

Пожалуйста, обратите внимание на надежный XML ниже и дайте мне знать, если вам понадобятся дополнительные предложения. :) Я предоставил больше, чем вы просили.

ВВОД XML:

<?xml version="1.0" encoding="utf-8"?>
    <content>
      <first>Paragraph-1</first>
      <likes>like-1</likes>

      <first>Paragraph-2</first>
      <comment>Comment-2</comment>
      <likes>like-2</likes>

      <first>Paragraph-3</first>
      <comment>Comment-3</comment>

      <first>Paragraph-4</first>
      <comment>Comment-4</comment>
      <likes>like-4</likes>
    </content>

XSLT-код:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:template>

  <xsl:template match="content">
    <xsl:element name="content1">
      <xsl:apply-templates select="node()|@*"/>
    </xsl:element>
  </xsl:template>

  <xsl:template match="first">
    <xsl:variable name="count" select="count(following-sibling::first)"/>
    <xsl:element name="block">
      <aaa>
        <xsl:apply-templates select="node()|@*"/>
      </aaa>
      <xsl:for-each select="following-sibling::comment[1][count(following-sibling::first) = $count]">
        <bbb>
          <xsl:apply-templates select="node()|@*"/>
        </bbb>
      </xsl:for-each>
      <xsl:for-each select="following-sibling::likes[1][count(following-sibling::first) = $count]">
        <ccc>
          <xsl:apply-templates select="node()|@*"/>
        </ccc>
      </xsl:for-each>
    </xsl:element>
  </xsl:template>
  <xsl:template match="comment|likes"/>

</xsl:stylesheet>

Выходной XML:

<?xml version="1.0" encoding="utf-8"?>
<content1>
  <block>
    <aaa>Paragraph-1</aaa>
    <ccc>like-1</ccc>
  </block>

  <block>
    <aaa>Paragraph-2</aaa>
    <bbb>Comment-2</bbb>
    <ccc>like-2</ccc>
  </block>

  <block>
    <aaa>Paragraph-3</aaa>
    <bbb>Comment-3</bbb>
  </block>

  <block>
    <aaa>Paragraph-4</aaa>
    <bbb>Comment-4</bbb>
    <ccc>like-4</ccc>
  </block>
</content1>

Это работает как драгоценный камень !!!!!! : D

Вот пример XSLT 2.0:

<xsl:stylesheet
  version="2.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output indent="yes"/>
  <xsl:strip-space elements="*"/>

  <xsl:param name="start-name" select="'a'"/>
  <xsl:param name="nchars" select="3"/>
  <xsl:variable name="start-index" select="string-to-codepoints($start-name)"/>

  <xsl:template match="content">
    <content1>
      <xsl:for-each-group select="*" group-starting-with="first">
        <block>
          <xsl:apply-templates select="current-group()"/>
        </block>
      </xsl:for-each-group>
    </content1>
  </xsl:template>

  <xsl:template match="content/*">
    <xsl:variable name="pos" select="position()"/>
    <xsl:element name="{string-join(for $c in 1 to $nchars return codepoints-to-string($pos - 1 + $start-index), '')}">
      <xsl:apply-templates/>
    </xsl:element>
  </xsl:template>

</xsl:stylesheet>